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Help with a chemistry calorimetry problem?
Nick and Katie placed 150.0 mL of 25°C water in a Styrofoam cup calorimeter. They then dropped in a piece of aluminum that had been in 100°C boiling water. The temperature of the resulting solution increased to 35°C. What was the mass or the piece of aluminum metal? (Specific heat of liquid water= 4.184 J/g°C. Specific heat of aluminum= 0.89 J/g°C).
1 Answer
- Anonymous7 years agoFavorite Answer
The only formula needed here is Q = m Cp dT , Cp is specific heat, and dT is change in temp.
the calorimeter makes the system adiabatic, so the heat from the aluminum is transferred only to the water. Now,
m Cp dT (water) = m Cp dT (aluminum)
mass of water is 150g (if density is 1)
Cp of water is 4.184 J/g K
dT of water is (increasing) 10°C
Cp of aluminum is 0.89 J/g K
dT of aluminum is (decreasing) 65°C
now, the mass of aluminum is m Cp dT (water) / Cp dT (aluminum) = 108.49 g