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Mathematics percentage odds question?
The statistic below is a real statistic (numbers) but the situation (words) have been changed.
If pink cars make up just 1% of the miles covered on uk roads yet pink cars are 21% more likely to be involved in accident. How much more likely are you to involved in a pink car than any other coloured car
Thank you
2 Answers
- Anonymous7 years agoFavorite Answer
If 21 percent of pink cars have a wreck and 1 percent of the cars on the road are pink, then you would have a .21% chance of having a wreck with a pink car providing that you do not drive a pink car. If you were driving a pink car then your chances of being in wreck with another pink car would go down minutely depending on how many cars total drive on the road. Also if you were driving a pink car we would also need the statistic for how likely is someone to be involved in a wreck with a car as the same color as theirs. This could only be figured if we had the statistics of what percent of cars are what color and what percent of cars that are a certain color are involved in an accident with the same colored car. For instance if there are only 100 cars that drive on the road and 1% of them are pink then you would have a 0% chance of hitting a pink car if you are driving a pink car. Then we also would need to know the definition of a wreck because what if a wreck means that a car is in a wreck, not how likely your car is to be in a wreck with another type of car. So from my example if there are 100 cars on the road and you drive a pink car, then you wreck your pink car. You are 100% likely to be involved in a wreck with a pink car because you are driving a pink car. Also if you drive the only pink car on the road and have a wreck in it then 100% of the pink cars on the road would have a wreck. So actually if you are driving a pink car and you have a wreck the statistic would increase or decrease depending on your definition of wreck. Also to deal with the first problem we would also need to know these statistics on the type of car you are driving. Such as what percentage of cars on the road are the same color as yours and how often does your color of car get into a wreck. Then you would take the chances of your color of car being in a wreck and compute the odds of how likely they are to pass a pink car. For example if your color of car was blue and 10% of the cars on the road are blue and 10% of the blue cars on the road usually have a wreck, then the chances of a blue car having a wreck would be .1%. Now I say what are the chances of a blue car wrecking into a pink car and the question you ask is how likely is a blue car and a pink car to pass each other on the road. The answer is (1%) (10%) = (1/100) (10/100) = 10/10000 = 1/1000 = .1%. So a pink car and a blue car will pass each other on the road .1% of the time. Now we have to figure how likely it will be that they have a wreck. The answer to this is (21%) (10%)(.1%) = 21/100 (10/100) (1/1000) = 210/10000000 = 21/1000000 = .000021% chance that a blue car will be involved with a pink car in a wreck. This is not entirely accurate but close to actually solve this type of problem we would need the percentage of total wrecks. What I mean is what percent of cars that had a wreck were pink? So as squid said your question isn't really clear but I hope I gave you something to go off of. Also this entire post that I made may be irrelevant because in your question you stated that pink cars are 21% more likely than...... more likely than what?
You could have also meant something else. If I take what you said literally then you are implying that 1% of cars are 21% more likely to get into a wreck than 99% of the cars on the road. So now we have a formula. If x= the percent in which you are likely to have a wreck then .21x= the percent of pink cars involved in a wreck then other cars. If we take .21x+.79x=x so you are 79% less likely to be involved in an accident with a car that is not pink. Then we can say that if y= the amount of cars on the road then .01y= the amount of pink cars on the road and we could say that .01y+.99y=y. So you have a 99% chance of driving a car that is not pink. So the answer is you have a .21x(.99y)= percent of chance of how more likely you are to be involved in an accident with a pink car.
- SquidLv 77 years ago
You question is unclear.
If you are driving a pink car and want to know what your chance of having an accident is, your data is irrelevant. Macro data on averages does not apply to a single driver, your personal driving skill and other factors would override the average.
If you are driving a non-pink car and want to know what your chances of being in an accident with a pink car, your data is all insufficient. Perhaps pink cars are driven at night by crazy people that cause a lot of accidents, but you only drive during the day so you never have an accident with a pink car. Or maybe all the pink cars are driving around london causing lots of accidents and you are in Portsmouth.