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Calculating pH?
If the concentration of Ca(OH)2 is 4.00 x 10^-3, calculate the pH
So... I wrote down the formula
Ca(OH)2 --> Ca + 2(OH)
Since the concentration of Ca(OH)2 is 4.00 x 10^-3 I think the concentration of OH would be double that? So 8.00 x 10^-3?
So, then I calculated the pOH
-log(8.00x10^-3) = 2.10 and then pH = 11.9
Is this correct?
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