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How do I find f^-1(x) of the function f(x)= √x-9 ?
Find f^-1 and state its domain and range
√ x-9
Is it to basically find out the inverse of the function? How do I do this?
1 Answer
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- Iggy RockoLv 77 years agoFavorite Answer
Substitute y for f(x) temporarily for convenience.
y = √x - 9
Swap x's and y's and solve for y.
x = √y - 9
x + 9 = √y
(x + 9)^2 = y
f^-1(x) = (x + 9)^2
The domain of f(x) is [0, ∞) so the range of f^-1(x) = [0, ∞).
The range of f(x) = [-9, ∞) so the range of f^-1(x) = [-9, ∞).
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