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Partial Fraction of (-s^2+10s-13)/(s^2*(s-3))?
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- MichaelLv 47 years agoFavorite Answer
-s^2 +10s -13 = A(s)(s-3) + B(s-3) + Cs^2
A+C=-1
-3A +B = 10
-3B = -13
B=13/3, A =-17/9, C= 8/9
===> (-17/9)*(1/s) + (13/3) *(1/s^2) + (8/9) *(1/(s-3))
Whick looks to have laplace inverse of:
-17/9 + (13/3) x + (8/9) e^(3x)
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