Help with writing slope intercept form?!!!?

Slope intercept form- y=mx+b

So for the first one:

Because the point is (0, 0) that you already know it is the intercept, and because the line they gave you is parallel to the other, they have the same slope. So the equation is y=(2/3)x

For the second:

You need to put the equation y+2=4(x-1) into slope intercept. So that is y=4x-6

Now you take the points they gave you (1, -3) and put those into the equation:

y-y1= m(x-x1) The four is the slope (parallel so same slope)

Now you put in the point (1, -3)

y+3= 4(x-1) and now you put it into slope intercept form-

y= 4x-4 and that is the second equation :)

For the third:

This one is perpendicular not parallel, so they don't have the same slope

To find the slope you take the negative reciprocal of the original

So the slope of the original is 5 so the negative reciprocal is -1/5

Now you put it into the equation y-y1= m(x-x-)

So y+2= -1/5(x-1) now you put that into slope intercept form

y= (-1/5)x+ (-9/5)

:)