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One algebra questions, please help me!?
Determine the equation of the parabola in the form y=ax2 + bx + c given the focus (2, 5) and directrix y=3
1 Answer
- scott8148Lv 77 years ago
the vertex is midway between the focus and the directrix
___ it is located at (2,4)
the focus is above the vertex, so the parabola opens upward
using the vertex form ___ y = a (x - 2)^2 + 4
___ the a coefficient is equal to 1 / (4p) ___ where p is the distance from the vertex to the focus
___ in this case, y = ¼ (x - 2)^2 + 4
y = ¼ x^2 - x + 5