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Difficult maths question (atleast for me)?

I'm trying to figure out what percentage of marijuana smoker in US have schizophrenia based from these numbers.

US population 313 million

24 million smokers

Schizofrenia population 2.2 million

Which percentage of of the percentage of smokers have schizofrenia?

3 Answers

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  • Anonymous
    7 years ago

    I used to hit it a bit, i was having symptoms long before that though.

    No, weed, or drugs in general do not cause this "disease", which isn't even a disease, they, whoever they are can get anyone at anytime really. It's da troof!

    Last time i smoked though something horrible happened, i hit it two or three times and sat down and ******* pa pow they began to look at me from above! Now, these things are the worst things you will ever meet, you think people are bad, not compared to these arseholes.

    They just began to stare at me from their seat of powers, they enjoyed my terror and realization of what they were to. I began to shiver deep within just from the sight of them and the feel of them.

    And they grinned at me.

    It was bad to say the least.

    There may be a system to this "disease", maybe people might want to look into it.

  • 7 years ago

    Genius! thanks allot bro have a great day!

  • 7 years ago

    Out of 313 M there are 24 M smokers

    Or, out of 1 there are 24 M / 313 M smokers

    So, out of 100, there are (24 M / 313 M)*100 = (24/313)*100 = 2400/313 = 7.67 smokers.

    So, 7.67 % of US population smoke.

    Similarly, out of 24 M smokers 2.2 M have schizophrenia.

    So, out of 100 it will be (2.2 / 24)*100 = 220/24 = 9.17

    So, 9.17 % of smokers have schizophrenia.

    Out of 313 M, 2.2M have schizophrenia.

    So, out of 100 it will be (2.2/313)*100 = 0.7

    So, 0.7 % of US population have schizophrenia.

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