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Probability Help ? (Difficult)?
If P(A) = .3, P(B) = .3, P(C) = .4, P(A and B) = .1, P(A and C) =.2, P(B and C) = .2,
P(A and B and C) = .1...Then P(A or B or C) = ? I have no idea how to solve this.
1 Answer
- Anonymous7 years agoFavorite Answer
P(A or B or C)
= P( (A or B) or C)
= P(A or B) + P(C) - P( (A or B) and C) ....(i)
P(A or B)
= P(A) + P(B) - P(A and B) = 5 ...(ii)
P( (A or B) and C)
= P(A and C) + P(B and C) - P(A and B and C)
= 3 ...(iii)
(i),(ii),(iii)
5 + 4 - 3 = 6
P(A or B or C) = 6
Complexity!!
but
It is easy to think of using Figure.
P(A or B or C) = 6 as shown in the following Figure.
