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Q asked in Science & MathematicsMathematics · 7 years ago

Find the volume of the solid generated by revolving the regions bounded by the graphs of the equations around the line x=6?

y=sqrtx

y=0

x=3

1 Answer

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  • telsaar
    Lv 4
    7 years ago

    Dv= 2*pi* R dx dy = 2*pi * (6-x) dx dy

    Double integral:

    Integrate over X from Y^2 to 3

    Then integrate over y from 0 to sqrt 3

    I got Volume = 91.415

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