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Please help me solve these problems!!?
1. 3/4 [4/(7-4)]
2. 2/3 [3/(2*1)]
3. 6* 1/6 +5 (12/4-3)
4. 6(1/2*n)=6
5. 0.25+1.5= n+1.5
I solved all the problems, but I got different answers when I checked my answers. So, I would like to see what others get. Please show me how you work it out, just so I can get an example of how to do it.
1 Answer
- Random StrangerLv 67 years agoFavorite Answer
I assume you are learning the standard order of operations, which you may call PEDMAS or BEDMAS.
Repeatedly:
Perform operations in parentheses or brackets first.
Perform exponentiation next.
Perform division and multiplication from left to right as they occur.
Perform addition and subtraction left to right as they occur.
1.
3/4*[4/(7-4)] =
3/4 * 4/3 =
12/12 =
1
2.
2/3 * [3/(2*1)] =
2/3 * 3/2 =
6/6 =
1
3.
6*1/6 + 5(12/4-3) =
1 + 5(3 - 3) =
1 + 5*0 =
1 + 0 =
1
4.
6(1/2*n) = 6
Remember to do multiplication left to right as they occur
6(1/2*n) = 6
6*(n/2) = 6
6n/2 = 6
3n = 6
n = 6/3
n = 2
5.
0.25 + 1.5 = n + 1.5
Subtract 1.5 from both sides.
0.25 + 1.5 - 1.5 = n + 1.5 - 1.5
0.25 + 0 = n + 0
0.25 = n
