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Use substitution of the solve the systems of equations?
Can you give me the answers to this
1) (the order pair should be -3, 3)
x-2y = -9
-x + y = 6
2) (the order pair should be -5, -3)
x-2y=1
-x+y=2
3) (the order pair should be 1, 0)
3x+4y=3
3x+y=3
4) (the order pair should be 6, 5)
x= y+1
4x-y=19
5) (the order pair should be 0, -2)
x-4y=8
-3x+y=-2
6) (the order pair should be 5, 7)
x-2y=-9
-x+y=2
if not all atleast anwer one of the questions if you can.
1 Answer
- 7 years ago
Hey.
This is a simultaneous equation, meaning you're trying to get rid of either x or y by either adding or subtracting. It also means this answer's going to be quite long, so just read it one line at a time and you should understand everything fine.
x -2y = -9
-x +y = 6
For this one, it's quite easy , since we have an x and a -x. We can use these.
Add the second equation to the first, if one's positive and the other's negative. You subtract if they're the same.
x -2y = -9
-x +y =6
0x -y = -3
As you can see, this leaves us with something we can solve quite easily
-y = -3
y=3
From this point, you put what you just got into one of the equations
-x +3 =6
-x= 3 (6-3)
-x=3 so x=-3
Then, you substitute in what you just got again to check your answer
-3-6=-9
So for this question, x=-3 and y=3
For questions like the 5th one, where you aren't given a pair you can use, you just simply
x -4y =8
-3x +y =-2
Multiply to find a pair
x -4y =8
-12x +4y =-8
-11x = 0
x=0
(0) -4y = 8
-y = 2
y = -2
Hope I've helped you out a bit :)