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Quartic Equation with 1 real solution?

3 Answers

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  • 7 years ago
    Favorite Answer

    It will have to have at least 1 complex coefficient. All real coefficients implies imaginary solutions come in pairs. So, either 2 complex solution and 2 real solutions or 4 complex solutions and no real solutions.

    If you allow complex coefficients then for example

    x^4 - i x^3 + 4x^2 - 4i x = 0

    has one real solution, x=0, and 3 complex solutions, x=i, x=2i, and x=-2i.

  • david
    Lv 7
    7 years ago

    yes x^4 = 0

    one real solution is x = 0, no other real solutions

  • 7 years ago

    (ax -- b)(cx -- di) = 0 OR acx^2 -- x(bc + adi) +bdi = 0 ANSAWER

    where a, b, c, d are non-imaginary numbers.

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