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Write an equation of the line satisfying the given conditions?
Parallel to the graph of 4x + y = 9, passes through the point at (0,- 5)
3 Answers
- ?Lv 77 years ago
Firstly, you do not need to find the gradient!
The line parallel to 4x + y = 9 and passing through (x₀,y₀) is 4x + y = 4x₀ + y₀
Here the point is (0,- 5) so the line is 4x + y = 4*0 + -5 which simplified is: 4x + y = -5
This is the same form of the line you had in the question, but feel free to manipulate it into any form you require.
- 7 years ago
y = 9 - 4x. So gradient = -4.
Passes through (0,-5)
y+5 = -4(x-0)
y+5 = -4x
y = -4x -5.
Or straight lines always follow y=mx+c.
y = 9 - 4x. Gradient = -4.
Crosses y axis at -5. So c = -5.
y = -4x -5.
- Iggy RockoLv 77 years ago
4x + y = 9
y = -4x + 9 which has a slope of -4.
The equation of the parallel line is
y - (-5) = -4(x - 0)
y + 5 = -4x
y = -4x - 5
