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2 Answers
- 7 years ago
First thing you need to do is solve for y, so that the equation will be in y=mx+b form, where m is the slope and b is the y-intercept (the y-value where the line crosses the y axis.
Your equation is 2x+3y-8=0
Step 1: Add 8 to both sides: 2x+3y=8 (The 8 on the left side gets canceled)
Step 2: Subtract 2x from both sides: 3y=8-2x (2x on the left side gets canceled)
Step 3: Divide both sides by 3: y=(8/3)-(2/3)x (The 3 on the left side gets canceled)
So now your equation is y=(8/3)-(2/3)x
I'm going to rearrange it to match the y=mx+b form. Now we have: y=(-2/3)x+(8/3)
Remember, m is the slope. So what is takes the place of m in the equation above?
-2/3.
The slope of the line is -2/3
- 7 years ago
by slope i assume you mean gradient. this can be found easily by rearranging your equation, into the form Y=MX + C, where M is the gradient.
first, add 8 to both sides, then subtract 2X from both sides, so you get
3Y=-2X + 8
then, divide both sides by 3, so the equation, in the form y=mx+c is
Y=-2/3X + 8/3
meaning the gradient is -2/3
