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From the enthalpies of reaction... Calculate delta H for the reaction.?
2C(s)+O2(g) --> 2CO(g) delta H=-221.0 kJ
2C(s)+O2(g) + 4H2(g) --> 2CH3OH(g)
delta H = -402.4 kJ
Calculate delta H for the reaction
CO(g)+2H2(g) -->CH3OH(g)
2 Answers
- ChemTeamLv 77 years ago
reverse first data equation and divide by 2 ---> this gets one CO on the left
divide second data equation by 2 ---> gives us 2h2 and one CH3OH
CO(g) --> C(s)+(1/2)O2(g) delta H=+110.5 kJ
C(s)+(1/2)O2(g) + 2H2(g) --> CH3OH(g) delta H = -201.2 kJ
Add the two equations together and the C and the 1/2O2 will cancel and you target equation is what is left.
Add the two enthalpies for the final answer.
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