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Probability and Statistics-Poisson distribution.?
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- M3Lv 77 years agoFavorite Answer
The poisson parameter for 1/2 sq. inch will be (1/2)*10 = 5,
and indicated Pr = sum e^-5 *5^k/k!, k = 0 to 5
= e^-5(1+ 5 +5^2/2! + 5^3/3! + 5^4/4! + 5^5/5!) = 0.6160 <-----
- 7 years ago
Let X, the number of flaws on the surface of a randomly selected boiler of a certain type, have Poisson distribution with (mu)=10 per square inch.
Find
P(number of flaws on a half square inch surface does not exceed 5)
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