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Need help with a math problem?
Let L be the line given by the equation y=26-3x.
a. Find the equation of the line that is parallel to L and passes through the points (4,-9)
b. Find the equation of the line that is perpendicular to L and passes through the points (-6,7)
1 Answer
- hayharbrLv 76 years ago
Parallel lines have equal slopes and as you know, if y = mx + b, m is slope so this line has slope -3 and so will any parallel line. That's y = -3x + b. Plug in 4 for x and -9 for y to see what b is:
-9 = (-3)4 + b
-9 = -12 + b
3 = b so y = -3x + 3
and perpendicular lines have opposite reciprocal slopes so that would be + 1/3. Again plug in (-6,7) for (x,y) to get b
7 = 1/3 (-6) + b
7 = -2 + b
9 = b so y = 1/3 x + 9
hope that helps
