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Wien's law?
Suppose the peak of a particular star's spectrum occurs at 6,000A (a) use Wien's law to calculate the stars surface temperature. (b) if a star were a factor of four hotter, at what wavelength would its spectrum peak? In what part of the electromagnetic spectrum is this peak?
1 Answer
- poornakumar bLv 76 years ago
Wien's law : λ T = 2.898
where λ is peaking wavelength in mm (for the sake of convenience) & T is the temperature in degrees Kelvin.
If λ = 6000 Ậ = 0.0006 mm,
T = 2.898 / 0.0006 = 28980 / 6 = 4830 K.
As λ ∝ 1/T
since λ = 2.898/T, ... inversely proportional to Tm
as T increases, λ decreases by the same factor (of four in your problem).
The λ will be ¼ ͭ ͪ of its previous value
6000 Ậ / 4 = 1500 Ậ in UV region..
Source(s): Clarks Tables
