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Solving trig ratios?
cos(x)= -(1/8) and between pi and 3pi/2
using pythagorean theorem I get
adj=1
opp=sqrt(65)
hyp=8
sin(x)= -(sqrt(65)/8)
tan(x)= sqrt(65)/1
cot(x)= 1/sqrt(65)
sec(x)=-(8/1)
csc(x)=-(8/sqrt(65))
Although the program says these are wrong except for sec(x).
I'm not sure if I messed up the process or just the negatives. Since its in the bottom left corner I thought everything would be negative except for tan and cot.
Thanks for the help
1 Answer
- 6 years ago
Oh I see, the opposite side wouldn't be sqrt(65),
it would be sqrt(64 - 1) = sqrt(63).
You just used the Pythagorean theorem the wrong way :P.