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Jason
Jason asked in Science & MathematicsMathematics · 6 years ago

Find the domain of this trig function?

f(x)=sqrt(tan(2x+π))

Allright, so i know you cannot have a zero under the square root sign and that tangent cannot equal π/2+nπ.

So should i try to find the domain of the tan function and see where it is greater than zero?

If so, how would i go about doing that?

2 Answers

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  • ted s
    Lv 7
    6 years ago

    so you need to solve 0 ≤ 2x + π < π / 2 to get to A ≤ x < B...now add n π / 2 to both A & B

  • alex
    Lv 7
    6 years ago

    f(x)=sqrt(tan(2x+π)) =sqrt(tan(2x)) --> k pi ≤ 2x < kpi + (pi/2) ---> k (pi/2) ≤ x < kpi/2 + (pi/4)

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