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The line 4y-3x=7 meets the curve 3x^2 -8y=-5 at P and Q. Find the gradient of the curve at P and Q??? How do i do it?
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- Elizabeth MLv 76 years ago
First solve the two equations simultaneously to find the coordinates of P and Q. This gives x=-1 and x=3.
From the equation of the curve,
8y=3x²+5 so
8dy/dx=6x and you can now get the gradient (dy/dx) at the two points.
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