Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
PHYSICS HOMEWORK HELP: Gravitation and Satellites?
This is a two part question.
1. The equation that governs the circular orbit of a satellite is T = 2(pi)√(r3 / Gme) where me is the mass of the earth, which is approximately 6 x 1024kg. Assuming a circular orbit, to achieve an orbit at 20,000km, what would the speed need to be?
2. Which of the symbols in the equation for the period of the orbit from #1 are constants?
Please show me all the formulas and steps you used. I need to solve more questions like this!
Thank you for your help in advance.
2 Answers
- ?Lv 76 years agoFavorite Answer
1. Is that 20 000 km from the surface, or from the earth's center?
I'll assume the former; then r = 6.371e6m + 2e7m = 2.6371e7 m
T = 2π√((2.6371e7m)³ / (6.674e-11N·m²/kg² * 6e24kg))
T = 42 521 s
Then v = 2πr / T = 2π * 2.6371m / 42521s = 3897 m/s ◄
IF the orbit radius is 2e7 m, then
T = 28 084 s
and v = 4475 m/s
2. Excluding the digits "2" and "3", π, G and Me are constants.
Hope this helps!
