Maths: EASY LOGARITHM: How to solve for k? Log base k 27=-3/2?

log-k(27) = -3/2

If we make both sides of the equation an exponent over a base of "k", that and the log of the same base will cancel out leaving only the 27 inside. Now we have:

27 = k^(-3/2)

Now if we take both sides to the (-2/3) power, we get k by itself and our solution:

k = 27^(-2/3)

Turn the fraction form into a radical form:

k = ∛(27^(-2))

That simplifies to:

k = 3^(-2)

and simplifies again:

k = 1/9

Okay start with log base k 27=-3/2

Next you want to get rid of base k so k^(-3/2)=27

Now you want k to the power of one so (k^-3/2)^(-2/3)=27^(-2/3)

K=27^(-2/3) solve for k and thats ypur answer