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Someone please do this geo question for me with all work?please!?
Two observers simultaneously observe an airplane overhead
and between them. They measure their angle of elevation to the airplane and obtain 48 and 73.mThe airplane is 1.7 mi above the point shown in the figure. What are the distances, x and y, of each observer from the point directly below the airplane? Round your answers to the nearest hundredth of a mile.
1 Answer
- The MeLv 66 years ago
This problem uses the law of sines
You can find the angles at the top of the triangles by subtracting
Let A be the point at the top, where the plane is
Let B be the point on the ground
C is the point to the left, x units from B
D is the point to the right, y units from B
You have triangles ABC and ABD
ABC is a 90-48-42 triangle, with 42 at point A
ABD is a 90-73-17 triangle with 17 at point A
Sin(D)/d=Sin(A)/a
sin(73)/1.7=sin(17)/y
sin(17)*1.7/sin(73)=y
y=.52 miles
sin(48)/1.7=sin(42)/x
sin(42)*1.7/sin(48)=x
x=1.53
x=1.53 miles and y=.52 miles
