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1 Answer
- cidyahLv 76 years ago
The z-critical value for 96% confidence interval is 2.05
a. n=150 b. p^ = 43/150 = 0.2867
c. z* = 2.05
d. SE = sqrt [ p^(1-p^) / n] = sqrt { (0.2867)(0.7133) /150) ] = 0.0369
e. ME = (0.0369)(2.05) = 0.075645
Confidence interval:
phat-zval*sd = 0.2867 - (2.05)(0.0369)
phat-zval*sd = 0.2867 + (2.05)(0.0369)
f. 96 % confidence interval is ( 0.211 , 0.362 )
g. If repeated sampling was used, the true proportion of subscribers to Boston Globe from Beverley residents will be contained in the interval 96 percent of the time.