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PLEASE HELP DUE TOMORROW!!! Quadratics question!!!?
1 Answer
- davidLv 76 years ago
26. x^2 + 2x + 3 = p(x^2 - 2x -3) = px^2 - 2px -3p
(p - 1)x^2 + (-2p - 2)x + (-3p - 3) = 0
a = (p - 1), b = (-2p - 2), c = (-3p - 3)
to have real solutions the discriminant must be > or = 0
b^2 - 4ac > or = 0
(-2p - 2)^2 - 4(p - 1)(-3p - 3) > or = 0
4p^2 + 8p + 4 + 12p^2 - 12 > or = 0
16p^2 + 8p - 8 > or = 0
2p^2 + p - 1 > or = 0
(2p - 1)(p + 1) > or = 0 <<< you can take it from here