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calculate the total value of delta H for, 4fe + 3o2 yields 2fe2o3 delta H = -1644kj, if 3.54 moles of fe2o3 are produced?
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- BobbyLv 76 years ago
4Fe + 3O2 = 2Fe2O3 ... delta H = -1644kj,
note this heat is produced when 2 moles of Fe2O3 are formed
we have 3.54 moles so
delta H = 1644 * 3.54 / 2 kJ = 2910 kJ of heat
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