Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Hydrostatic Force question?
The two sides of a v-shaped water trough are hinged to each other at the bottom where they meet making an angle of 45 degrees with the ground from both sides .Each side is 0.75 m wide and the two parts are held together by a cable and turnbuckle placed every 6 m along the length of the trough. Calculate the tension in each cable when the trough is filled to the rim.
I'm using F=pghA, but I keep getting an answer that is nowhere close to the given answer of 5510 N
1 Answer
- Born YesterdayLv 76 years agoFavorite Answer
This looks like a Calculus problem, but the simple geometry
succumbs to Algebra. The trough is a square bisected by a diagonal.
From the image below, if the sides are .75m the cross sectional
area is (.75m)²/2 = .28125m²
The water's depth is √2/2 × .75m ≈ .53m which is half
the diagonal.
Both water pressure and surface area are linear
with depth.
.53m/2 × 9,807kg/m³ = 2,599 N
The trough's area is 6m×.75m = 4.5m²
Total force 4.5×2,599 N/m² = 11,695 Newtons
Are you sure the answer is 5,510?
