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Urgente.. disequazione esponenziale, grazie?
2*3^-x-3^x > 1
1 Answer
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- lucianoLv 76 years agoFavorite Answer
2·3^(-x) - 3^x > 1
2 - 3^(2·x) > 3^x
pongo:
3^x = z
z^2 + z - 2 < 0
risolvo:
-2 < z < 1
qundi:
-2 < 3^x < 1
per cui risulta:
x < 0
Noto l'andamento della funzione esponenziale!
Ciao Luciano
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