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Urgente.. disequazione esponenziale, grazie?

2*3^-x-3^x > 1

1 Answer

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  • 6 years ago
    Favorite Answer

    2·3^(-x) - 3^x > 1

    2 - 3^(2·x) > 3^x

    pongo:

    3^x = z

    z^2 + z - 2 < 0

    risolvo:

    -2 < z < 1

    qundi:

    -2 < 3^x < 1

    per cui risulta:

    x < 0

    Noto l'andamento della funzione esponenziale!

    Ciao Luciano

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