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? asked in Science & MathematicsMathematics · 6 years ago

What is the area of a regular nonagon with a radius of 14 in?

I need the work plz

Update:

It's either

566.9

141.7

70.9

Or 142903.1

1 Answer

Relevance
  • DWRead
    Lv 7
    6 years ago

    Divide the nonagon radially into 9 identical isosceles triangles.

    each vertex angle is 360/9 = 40°, and so base angle is 70°.

    Let h and b be the height and base of a triangle.

    h = 14sin(70°)

    b = 28cos(70°)

    area of triangle = bh/2 ≅ 54 in²

    area of nonagon 9·54 ≅ 485.95

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