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Help with trig please ASAP?
use the given inforation to evaluate sin(a + B)
tan a 4/3, cos B = -12/13, neither a nor B are in quadrant III
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- 6 years ago
if tan a = 4/3 then y = 4, x= 3, r = 5 Pythagorean Theorem
if cos B = -12/13, then x = -12, y = 5, r = 13
sin (a+B) = sin a cos B + cos a sin B = (4/5)((-12/13) + (3/5)(5/13) = -48/65 +15/65 = -33/65
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