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The difference of two positive numbers is 7 and the sum of their squares is 85. Find the numbers.?

3 Answers

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  • donpat
    Lv 7
    6 years ago

    You have :

    -----------------------

    A - B = 7 ----------> B = A + 7

    A^2 + B^2 = 85

    A^2 + ( A + 7 )^2 = 85

    A^2 + 49 + 14 A + A^2 = 85

    2A^2 + 14A - 36 = 0

    A = { (- 14 ) +/- SQRT [ ( 14 )^2 - ( 4 ) ( 2 ) ( -36 ) ] } / { ( 2 ) ( 2 ) }

    A = { -14 +/- SQRT [ ( 196 ) + ( 288 ) ] } / { 4 }

    A = { -14 + 22 } / { 4 } = 2

    A = { --14 - 22 ) / { 4 } = - 9 --------> Unacceptable because negative

    A = 2

    B = A + 7 = 9

    Answers: A = 2 B = 9 <------------------

    Check the answers :

    ( A )^2 + ( B )^2 = ( 2 )^2 + ( 9 )^2 = 4 + 81 = 85 ---->[ OK ]

  • Kike
    Lv 7
    6 years ago

    x = the greater number

    x - 7 = the smaller number.

    x ^2 + (x - 7 ) = 85

    x^2 + x^2 - 14x + 49 = 85

    2x^2 - 14x + 49 - 85 = 0

    2x^2 - 14 x -36 = 0

    Simplifying the equation

    x^2 - 7x - 18 = 0

    Factoring

    (x - 9)(x +2 ) = 0

    x - 9 = 0 ; x = 9 (valid solution) : The greater number

    x + 2 = 0 ; x = -2

    x - 7 = the smaller number

    9 - 7 = 2 (the smaller number)

    So, the numbers are 9 and 2.

  • 6 years ago

    2 and 9 :)

    2 squared is 4

    9 squared is 81

    81 + 4 is 85

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