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The intersection of where the line meets a circle. Y=-2+6 and (x-2)2 and (y+3)2 = 10
2 Answers
- Anonymous6 years ago
I'm assuming that the equation of the line is actually y=-2x+6. The intersection of two lines is where both equations are satisfied so we can use both equations to solve for x and y. So by plugging in "-2x+6" everywhere we see y we have:
((-2x+6+3)^2)+((x-2)^2)=10
4x^2-36x+81+x^2-4x+4=10
5x^2-40x+75=0
x^2-8x+15=0
(x-5)(x-3)=0
So x=5 and x=3 work.
Plugging those into y=-2x+6 we get y=-2(5)+6=-4 and y=-2(3)+6=0
So the solutions (5,-4) and (3,0) which are all the points of intersection.
- Anonymous6 years ago
The formula is: **** + You =