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pls help ! ( limits equations) lim x->0 |x-a| / x^2-a^2?
its lim x-<0 -
1 Answer
- ?Lv 76 years agoFavorite Answer
No, it's probably x -> 0- .
The string you wrote in your update has no meaning at all.
I'm going to assume you want the limit as x approaches 0 from the negative domain. I think I have to consider whether "a" is positive or negative. If "a" is a positive number, then |x-a| = a-x when x is negative, and the limit will be -1/(x+a). If "a" is a negative number, then |x-a| = x-a when x is negative but near zero; so the the limit will be 1/(x+a). If a = 0, then you're looking at x -> 0- of |x|/x^2, which is +infinity.
