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Sharvani
Sharvani asked in Science & MathematicsChemistry · 6 years ago

What are the number of water molecules in 333g of Al2(SO4)3.18H2O?

2 Answers

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  • Roger the Mole
    Lv 7
    6 years ago
    Favorite Answer

    (333 g Al2(SO4)3·18H2O) / (666.4259 g Al2(SO4)3·18H2O/mol) × (18 mol H2O / 1 mol Al2(SO4)3·18H2O) ×

    (6.022 × 10^23 molecules/mol) = 5.42 × 10^24 molecules H2O

  • Sheldon
    Lv 5
    6 years ago

    18 x molec. wt. H20/molec. wt. Al2(SO4)3.18H2O x 33g= ?g H20

    ? g H2O/molec. wt H2O= ?moles H2O

    ?moles H2O x 6.02E-23 molecules/mole= ans.

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