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Help in Calculus!?
How do u do #49 and #51. Please tell me steps and not answers. Thx in advance.
2 Answers
- ted sLv 76 years ago
multiply top and bottom by [ √x + √a ] ; top and bottom by [ √ (16 + h ) + 4 ]...do the algebra , take the limit
- Anonymous6 years ago
limit x->a (x - a)/[sqrt(x) - sqrt(a)]
(x - a)/[sqrt(x) - sqrt(a)]
(x - a)*[sqrt(x) + sqrt(a)]/{[sqrt(x) - sqrt(a)]*[sqrt(x) + sqrt(a)]}
(x - a)*[sqrt(x) + sqrt(a)]/(x - a)
limit x->a sqrt(x) + sqrt(a) = 2sqrt(a)
limit h->0 [sqrt(16 + h) - 4]/h plug in and get 0/0 which is great as you
(d/dh sqrt(16 + h) - 4)/(d/dh h) = 1/[2*sqrt(h + 16)] = 1/8
