Nitrogen and hydrogen react to form ammonia acc to the following reaction: N2(g) + 3H2 ---> 2NH3(g)?

If 1000 g of H2 reacts with 2000 g of N2

Which one is the limiting reactant? And what's the mass of ammonia formed?

See, we've 28 g of Nitrogen and 6g of Hydrogen

I divided 2000/28 = 71.42 moles

And 1000/6 = 166.66 moles

The ratio is 1:3

This means 71.42 moles should give around 214 moles but we're getting less than the reqd amount. This means H2 is the LR, right?

I've been solving all limiting reagent qs like this. But I'm getting this particular question wrong by this method. Can anyone explain why?

Thanks a lot!