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Parabolas; find Vertex, focus, directrix?
(x+4)^2 =16(y+2)
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- ?Lv 76 years agoFavorite Answer
(x-h)^2 = -4p(y-k) => open downward
vertex: (h, k)
p: the distance between vertex and focus (or directrix)
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(x+4)^2 =16(y+2)
vertex: (-4, -2)
4p = 16
p = 4 => open upward
focus: (-4, 2)
directrix: y = -6
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