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Trigonometric functions help please?
Given cot(theta) is undefined and pi/2 <= theta <= 3pi/2 . Find the exact values of the six trigonometric functions of theta
What is theta?
Given theta = 10pi/3. Find the exact values of the six trigonometric functions of theta. How would you draw the angle? Find the reference angle.
3 Answers
- cidyahLv 76 years agoFavorite Answer
cot(θ) = cos(θ)/sin(θ)
θ lies in the second and third quadrant. when θ=pi, cot(θ) is undefined
sin(pi)=0
cos(pi)=-1
tan(pi) = sin(pi)/cos(pi) = 0
sec(pi) = 1/cos(pi) = -1
csc(pi) = 1/sin(pi) = 1/0 = undefined
cot(pi) = cos(pi) / 0 = undefined
----------------------
θ = 10pi/3
10pi/3 = 3pi + pi/3 = 2pi + (pi+pi/3) = 2pi+4pi/3 = 4pi/3 = pi+pi/3
θhe reference angle is pi/3 and θ lies in quadrant 3
sin(10pi/3) = sin(pi/3) = -*3/2 (sine is negative in quadrant III)
cos(10pi/3) = cos(pi/3) = -1/2 (cos is negative in quadrant III)
tan(10pi/3) = sin(pi/3) / cos(pi/3) = *3
cot(10pi/3) = 1/tan(pi/3) = 1/*3
csc(10pi/3) = 1/sin(pi/3) = -2 /*3
sec(10pi/3)= 1/cos(pi/3) = -2
- DWReadLv 76 years ago
cotθ = cosθ/sinθ
If cotθ is undefined, then sinθ = 0
arcsin(0) = 0, π, 2π, ...
π/2 ≤ θ ≤ 3π/2
θ = π
:::::
θ = 10π/3
θ' = 4π/3
sinθ' = -√3/2
cosθ' = -1/2
tanθ' = √3
you can do the rest