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If 15.83 mL of NaOH are required to titrate 15.00 mL of a 0.46 M oxalic acid solution, what is the concentration of the NaOH?

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  • Rais
    Lv 6
    6 years ago
    Favorite Answer

    The complete reaction between NaOH and oxalic acid is

    2NaOH + (COOH)2 = (COONa)2 + 2H2O

    2 mol 1 mol

    15.00 mL of a 0.46 M oxalic acid solution = 0.46 mol L-1x 0.015 L = 0.0069 mol of oxalic acid

    From the above reaction

    1 mol of oxalic acid requires 2 moles of NaOH for complete reaction.

    So 0.0069 mol of oxalic acid will require 2 x 0.0069 i.e. 0.0138 mol of NaOH

    Hence the concentration of NaOH = 0.0138 mol/0.01583 L = 0.87 M

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