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? asked in Science & MathematicsMathematics · 6 years ago

Given ABCD is a rhombus, m <ADB= 60, and DC=40. Find the length of EB?

E is in the middle btw

Update:

Would you solve using Pythagorean Theorem?

1 Answer

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  • Pope
    Lv 7
    6 years ago

    Point E is in the middle of what? Are you saying that E is the intersection of the diagonals? I will go with that.

    ∠ADB = 60° ... given

    AB = AD ... property of a rhombus

    ∠ABD = ∠ADB = 60° ... angles opposite equal sides in an isosceles triangle

    Triangle ABD is an equilateral triangle ... two 60° angles

    DB = DA = DC = 40 ... properties of equilateral triangle and rhombus

    EB = DB/2 = 20 ... Diagonals of a parallelogram bisect each other.

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