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Given ABCD is a rhombus, m <ADB= 60, and DC=40. Find the length of EB?
E is in the middle btw
Would you solve using Pythagorean Theorem?
1 Answer
- PopeLv 76 years ago
Point E is in the middle of what? Are you saying that E is the intersection of the diagonals? I will go with that.
∠ADB = 60° ... given
AB = AD ... property of a rhombus
∠ABD = ∠ADB = 60° ... angles opposite equal sides in an isosceles triangle
Triangle ABD is an equilateral triangle ... two 60° angles
DB = DA = DC = 40 ... properties of equilateral triangle and rhombus
EB = DB/2 = 20 ... Diagonals of a parallelogram bisect each other.