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Physics help please?

A 100 kg sofa 4 m long is carried by James and Sarah. James has the end, Sarah is holding the sofa 0.5 m from the other end. Some moron places a 50 kg box of books on the sofa on the very end of the sofa Sarah is holding. How much weight is Sarah holding now?

a) 300 N

b) 500 N

c) 700 N

d) 900 N

e) 1100 N

2 Answers

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  • 5 years ago
    Favorite Answer

    Let’s determine the weights of the sofa and box.

    For the sofa, weight = 100 * 9.8 = 980 N

    For the box, weight = 50 * 9.8 = 490 N

    This is a torque problem. I suggest that you draw a diagram of this problem. To solve this problem, I use the end of the sofa that James is holing as the pivot point. Since the weight of the sofa is at its center, it is 2 meters from the pivot point. The weight of the box is 4 meters from the pivot point. Let’s calculate these two clockwise torques.

    For the sofa, torque = 980 * 2 = 1960

    For the box, torque = 490 * 4 = 1960

    Total clockwise torque = 3920

    4 – 0.5 = 3.5 m

    This is Sarah’s distance from the pivot point.

    Counter clockwise torque = F * 3.5

    F * 3.5 = 3920

    F = 3920 ÷ 3.5 = 1120 N

    If you round this number to 2 significant digits, e is the correct answer.

  • Amy
    Lv 7
    5 years ago

    The forces must be balanced. Assuming both people are exerting upward forces with no horizontal components, the sum of those forces equals the total weight:

    J + S = 150kg * g

    From the round numbers of the answer choices, I'll guess they're rounding g to 10 m/s^2.

    And the torques must be balanced. Measuring torque around the center of the sofa:

    J and the weight of the box are both at 2m, and S is at 1.5m.

    J and the weight of the box produce torques in one direction and S produces torque in the opposite direction.

    Assuming symmetry, the weight of the two halves of the sofa exert equal and opposite torques, so those add to zero.

    J * 2m + 50kg * 10 m/s^2 * 2m = S * 1.5m

    This gives a system of equations to solve.

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