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Physics help please?
A 100 kg sofa 4 m long is carried by James and Sarah. James has the end, Sarah is holding the sofa 0.5 m from the other end. Some moron places a 50 kg box of books on the sofa on the very end of the sofa Sarah is holding. How much weight is Sarah holding now?
a) 300 N
b) 500 N
c) 700 N
d) 900 N
e) 1100 N
2 Answers
- electron1Lv 75 years agoFavorite Answer
Let’s determine the weights of the sofa and box.
For the sofa, weight = 100 * 9.8 = 980 N
For the box, weight = 50 * 9.8 = 490 N
This is a torque problem. I suggest that you draw a diagram of this problem. To solve this problem, I use the end of the sofa that James is holing as the pivot point. Since the weight of the sofa is at its center, it is 2 meters from the pivot point. The weight of the box is 4 meters from the pivot point. Let’s calculate these two clockwise torques.
For the sofa, torque = 980 * 2 = 1960
For the box, torque = 490 * 4 = 1960
Total clockwise torque = 3920
4 – 0.5 = 3.5 m
This is Sarah’s distance from the pivot point.
Counter clockwise torque = F * 3.5
F * 3.5 = 3920
F = 3920 ÷ 3.5 = 1120 N
If you round this number to 2 significant digits, e is the correct answer.
- AmyLv 75 years ago
The forces must be balanced. Assuming both people are exerting upward forces with no horizontal components, the sum of those forces equals the total weight:
J + S = 150kg * g
From the round numbers of the answer choices, I'll guess they're rounding g to 10 m/s^2.
And the torques must be balanced. Measuring torque around the center of the sofa:
J and the weight of the box are both at 2m, and S is at 1.5m.
J and the weight of the box produce torques in one direction and S produces torque in the opposite direction.
Assuming symmetry, the weight of the two halves of the sofa exert equal and opposite torques, so those add to zero.
J * 2m + 50kg * 10 m/s^2 * 2m = S * 1.5m
This gives a system of equations to solve.