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Math help?
Consider the second order IVP
y''+3y'+2y=g(t), y(0)=0, y'(0)=0
i) solve y(t) as y(t) = h(t)*g(t) and write down h(t)
ii) For g(t) given by g(t) =
function 1: 0, interval: 0<=t<3,
function 2: 1, interval: 3<=t
calculate h(t)*g(t)
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