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Laplace Transformation Problem?
Use formulas in the Laplace Transform table to compute
L^(-1) {[(s+1)/s^2] e^(-s)}
1 Answer
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- Anonymous5 years agoFavorite Answer
L^-1{[(1/s) + (1/s^2)]*e^(-s)}
The first one is easy as
stepfunction(t - 1) + L^-1(e^(-s)/s^2)
stepfunction(t - 1) + L^-1(e^(-s)/s^2)
stepfunction(t - 1) + (t - 1)*stepfunction(t - 1)
simplify to
t*stepfunction(t - 1)
graph as
-infinity < t < 1 then the function is zero
1 < t < infinity then function is f(t) = t
Source(s): http://tutorial.math.lamar.edu/pdf/Laplace_Table.p... 25 and 27
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