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tre
tre asked in Science & MathematicsMathematics · 5 years ago

How to factor x^2-4x-2=0?

5 Answers

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  • sepia
    Lv 7
    5 years ago

    x^2 - 4x - 2 = 0

    x

    = [4 ± √(16 + 8)/2

    Solutions:

    x = 2 - √6

    x = 2 + √6

  • Como
    Lv 7
    5 years ago

    [x² - 4x + 4] - 4 - 2 = 0

    [ x - 2 ]² = 6

    x - 6 = ± √6

    x = 6 ± √6

  • lenpol7
    Lv 7
    5 years ago

    This does NOT factor.

    Use either 'Completing the Square' or 'Quadratic Eq'n'.

    Completing the Square

    x^2 - 4x = 2

    ( x - 2)^2 - 4 = 2

    ( x - 2)^2 = 6

    x - 2 = sqrt(6)

    x = 2 +/- sqrt(6)

  • J
    Lv 7
    5 years ago

    x^2-4x-2 = (x-2-sqrt(6))(x-2+sqrt(6))

    If you want to solve the given equation, complete the square.

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  • Morningfox
    Lv 7
    5 years ago

    Us the quadratic formula. You know, the equation with ( -b +/- sqrt( b^2 - 4ac) ) / (2a)

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