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What is the sum of all the factors of the number: 181 216 437 286 500 000?
Hint: This number has prime factorisation 2^5 * 3^8 * 5^6 * 7^3 * 11^5
2 Answers
- ?Lv 75 years agoFavorite Answer
I didn't do it the way you probably want, but I got
858064863097915200
- nbsale (Freond)Lv 65 years ago
The formula is simple, just a product of sum of powers of the prime factors, which are easy to get by formula since they are just the sums of a geometric series.
1+2+4+8+16+32 = (2^6 - 1)/(2-1) = 63
1 + 3 + 3^2 + ... + 3^8 = (3^9 - 1) / (3-1) = 9841
Use (p^(n+1) - 1)/(p-1) for the other prime powers p^n. You get the idea.
Then you need a calculator that can handle all the digits.
The sum of the factors is the product of
63
9841
19531
400
177156
= 858,064,863,097,915,000 per Excel, but that dropped the last digit
= 858,064,863,097,915,200 per PC's built-in calculator.