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If n is a natural number and r is the remainder when n is divided by 3, then if t = 5 or 11, the sum r^2 + r + t is prime.?
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- ?Lv 75 years agoFavorite Answer
Since r is the remainder when n is divided by 3, then n can only be 0, 1, or 2
r = 0 ---> r² + r + t = t = 5 or 11 ----> both prime
r = 1 ---> r² + r + t = 2+t = 7 or 13 ----> both prime
r = 2 ---> r² + r + t = 6+t = 11 or 17 ----> both prime
So statement is true.
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