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If x=3sin(theta) What is -cos(theta) in terms of x using the method of triangles Answer is -sqrt(9-x^2)?
2 Answers
- Keith ALv 65 years agoFavorite Answer
Triangles:
Take 3 as the hypotenuse of a right triangle,
and x opposite the angle θ -- assuming θ is acute.
Then the third side - adjacent to θ, is √(9 - x²)
So cos θ = √(9 - x²) / 3 ,
-cos θ = -√(9 - x²) / 3 .
- Wayne DeguManLv 75 years ago
If x = 3sinθ then,
sinθ = x/3
Now, sin²θ + cos²θ = 1
i.e. (x/3)² + cos²θ = 1
=> cos²θ = 1 - (x²/9)
=> 9cos²θ = 9 - x²
so, cos²θ = (9 - x²)/9
=> cosθ = ±√(9 - x²)/3
Hence, -cosθ = -√(9 - x²)/3
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