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Dylan
Lv 6
Dylan asked in Science & MathematicsMathematics · 5 years ago

If x=3sin(theta) What is -cos(theta) in terms of x using the method of triangles Answer is -sqrt(9-x^2)?

2 Answers

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  • 5 years ago
    Favorite Answer

    Triangles:

    Take 3 as the hypotenuse of a right triangle,

    and x opposite the angle θ -- assuming θ is acute.

    Then the third side - adjacent to θ, is √(9 - x²)

    So cos θ = √(9 - x²) / 3 ,

    -cos θ = -√(9 - x²) / 3 .

  • 5 years ago

    If x = 3sinθ then,

    sinθ = x/3

    Now, sin²θ + cos²θ = 1

    i.e. (x/3)² + cos²θ = 1

    => cos²θ = 1 - (x²/9)

    => 9cos²θ = 9 - x²

    so, cos²θ = (9 - x²)/9

    => cosθ = ±√(9 - x²)/3

    Hence, -cosθ = -√(9 - x²)/3

    :)>

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