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Peace
Lv 5
Peace asked in Science & MathematicsMathematics · 5 years ago

geometric sequence?

Solve the nth term for the following progression which only has positive real numbers and has u_2=8 and u_6=128

3 Answers

Relevance
  • 5 years ago

    u_2 = 8, = a * r^1

    u_6 = 128, = a * r^5

    So 128 / 8 = (a * r^5) / (a * r)

    I.e., 16 = r^4

    So r = 2 (positive terms only)

    So a = 8 / 2 = 4

    (Determine (sic) the nth term: )

    u_n = a * r^(n - 1)

    = 4 * 2^(n - 1)

    = 2^(n + 1)

  • 5 years ago

    It could be any one of these geometric sequences:

    The first term is -4 and the common ratio is -2

    The first term is 4 and the common ratio is 2

    The first term is -4i and the common ratio is 2i

    The first term is 4i and the common ratio is -2i

    http://www.wolframalpha.com/input/?i=ar%3D8,ar%5E5...

  • ?
    Lv 7
    5 years ago

    u_2 = 8, u_6 = 128

    d = (128 - 8)/4 = 30

    u_1 = 8 - 30 = -22

    u_n = -22 + 30(n - 1)

    u_n = 30n - 52

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